MHT CET · Maths · Vector Algebra
If \(\overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}=4\), then \((\overrightarrow{\mathbf{a}} \times \hat{\mathbf{j}}) \cdot(2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})\) is equal to
- A 12
- B 2
- C 0
- D \(-12\)
Answer & Solution
Correct Answer
(D) \(-12\)
Step-by-step Solution
Detailed explanation
\((\overrightarrow{\mathbf{a}} \times \hat{\mathbf{j}}) \cdot(2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})=\overrightarrow{\mathbf{a}} \cdot\{\hat{\mathbf{j}} \times(2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})\}\)
\(
\begin{array}{l}
=\overrightarrow{\mathbf{a}} \cdot\{-3(\hat{\mathbf{j}} \times \hat{\mathbf{k}})\} \\
=-3(\overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}) \\
=-12 \quad(\because \overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}=4 \text { given })
\end{array}
\)
\(
\begin{array}{l}
=\overrightarrow{\mathbf{a}} \cdot\{-3(\hat{\mathbf{j}} \times \hat{\mathbf{k}})\} \\
=-3(\overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}) \\
=-12 \quad(\because \overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}=4 \text { given })
\end{array}
\)
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