MHT CET · Maths · Differentiation
If \((\mathrm{a}+\mathrm{b} x) \mathrm{e}^{\frac{\mathrm{y}}{x}}=x\), then \(x^3 \frac{\mathrm{~d}^2 \mathrm{y}}{\mathrm{d} x^2}\) is equal to
- A \(\left(\mathrm{y} \frac{\mathrm{dy}}{\mathrm{d} x}-x\right)^2\)
- B \(\left(x \frac{\mathrm{dy}}{\mathrm{d} x}-\mathrm{y}\right)^2\)
- C \(\left(x \frac{\mathrm{dy}}{\mathrm{d} x}+\mathrm{y}\right)^2\)
- D \(\left(\mathrm{y} \frac{\mathrm{dy}}{\mathrm{d} x}+x\right)^2\)
Answer & Solution
Correct Answer
(B) \(\left(x \frac{\mathrm{dy}}{\mathrm{d} x}-\mathrm{y}\right)^2\)
Step-by-step Solution
Detailed explanation
\( (\mathrm{a}+\mathrm{b} x) \mathrm{e}^{\frac{\mathrm{y}}{x}}=x \Rightarrow \ln(\mathrm{a}+\mathrm{b} x) + \frac{\mathrm{y}}{x} = \ln x \) \( \frac{\mathrm{y}}{x} = \ln x - \ln(\mathrm{a}+\mathrm{b} x) \)
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