MHT CET · Maths · Vector Algebra
If \(\bar{a}, \overline{\mathrm{~b}}, \overline{\mathrm{c}}\) are three unit vectors such that \(|\bar{a}+\overline{\mathrm{b}}|^2+|\bar{a}+\overline{\mathrm{c}}|^2=8\), then \(|\bar{a}+3 \overline{\mathrm{~b}}|^2+|\bar{a}+3 \overline{\mathrm{c}}|^2=\)
- A \(26\)
- B \(32\)
- C \(22\)
- D \(36\)
Answer & Solution
Correct Answer
(B) \(32\)
Step-by-step Solution
Detailed explanation
\(|\bar{a}|=|\overline{\mathrm{b}}|=|\overline{\mathrm{c}}|=1\) \((|\bar{a}|^2+|\overline{\mathrm{b}}|^2+2\bar{a}\cdot\overline{\mathrm{b}})+(|\bar{a}|^2+|\overline{\mathrm{c}}|^2+2\bar{a}\cdot\overline{\mathrm{c}})=8\)
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