MHT CET · Maths · Vector Algebra
If \(\bar{a}, \overline{\mathrm{~b}}, \overline{\mathrm{c}}\) are perpendicular to \(\overline{\mathrm{b}}+\overline{\mathrm{c}}, \quad \bar{c}+\bar{a}\) and \(\bar{a}+\overline{\mathrm{b}}\) respectively and \(|\bar{a}+\bar{b}|=2,|\bar{b}+\bar{c}|=6,|\bar{c}+\bar{a}|=4\), then \(|\bar{a}+\bar{b}+\bar{c}|=\)
- A \(2 \sqrt{6}\)
- B \(2 \sqrt{7}\)
- C \(3 \sqrt{6}\)
- D \(3 \sqrt{7}\)
Answer & Solution
Correct Answer
(B) \(2 \sqrt{7}\)
Step-by-step Solution
Detailed explanation
\( \bar{a} \cdot (\bar{b}+\bar{c})=0 \implies \bar{a} \cdot \bar{b} + \bar{a} \cdot \bar{c} = 0 \) \( \bar{b} \cdot (\bar{c}+\bar{a})=0 \implies \bar{b} \cdot \bar{c} + \bar{b} \cdot \bar{a} = 0 \)
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