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MHT CET · Maths · Vector Algebra

If \(\bar{a}, \overline{\mathrm{~b}}, \overline{\mathrm{c}}\) are perpendicular to \(\overline{\mathrm{b}}+\overline{\mathrm{c}}, \quad \bar{c}+\bar{a}\) and \(\bar{a}+\overline{\mathrm{b}}\) respectively and \(|\bar{a}+\bar{b}|=2,|\bar{b}+\bar{c}|=6,|\bar{c}+\bar{a}|=4\), then \(|\bar{a}+\bar{b}+\bar{c}|=\)

  1. A \(2 \sqrt{6}\)
  2. B \(2 \sqrt{7}\)
  3. C \(3 \sqrt{6}\)
  4. D \(3 \sqrt{7}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \sqrt{7}\)

Step-by-step Solution

Detailed explanation

\( \bar{a} \cdot (\bar{b}+\bar{c})=0 \implies \bar{a} \cdot \bar{b} + \bar{a} \cdot \bar{c} = 0 \) \( \bar{b} \cdot (\bar{c}+\bar{a})=0 \implies \bar{b} \cdot \bar{c} + \bar{b} \cdot \bar{a} = 0 \)