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MHT CET · Maths · Vector Algebra

If \(a, b, c\) are distinct positive numbers and vectors \(a \hat{\imath}+a \hat{\jmath}+c \hat{k}, \hat{\imath}+\hat{k}\)
and \(c \hat{\imath}+c \hat{\jmath}+b \hat{k}\) lie in a plane, then

  1. A \(c\) is A.M. of a and b
  2. B \(\mathrm{c}^{2}=0\)
  3. C \(\mathrm{c}\) is \(\mathrm{H} . \mathrm{M}\). of \(\mathrm{a}\) and \(\mathrm{b}\)
  4. D \(c\) is G.M. of a and b
Verified Solution

Answer & Solution

Correct Answer

(D) \(c\) is G.M. of a and b

Step-by-step Solution

Detailed explanation

(B)
since, three vectors are coplanar
\(\left|\begin{array}{lll}
\mathrm{a} & \mathrm{a} & \mathrm{c} \\
1 & 0 & 1 \\
\mathrm{c} & \mathrm{c} & \mathrm{b}
\end{array}\right|=0\)
Applying \(\mathrm{C}_{1} \rightarrow \mathrm{C}_{1}-\mathrm{C}_{2}\)
\(\left|\begin{array}{lll}
0 & a & c \\
1 & 0 & 1 \\
0 & c & b
\end{array}\right|=0\)
Expanding along \(C_{1}\), we get
\(-1\left(a b-c^{2}\right)=0 \Rightarrow a b=c^{2} \Rightarrow c\) is G.M. of a and b