MHT CET · Maths · Vector Algebra
If \(\bar{a}+\bar{b}, \bar{b}+\bar{c}, \bar{c}+\bar{a}\) are coterminous edges of a parallelepiped, then its volume is
- A 0
- B \(4[\overline{\mathrm{b}} \overline{\mathrm{a}} \overline{\mathrm{c}}]\)
- C \(3[\bar{a} \bar{c} \bar{b}]\)
- D \(2[\overline{\mathrm{a}} \overline{\mathrm{b}} \overline{\mathrm{c}}]\)
Answer & Solution
Correct Answer
(D) \(2[\overline{\mathrm{a}} \overline{\mathrm{b}} \overline{\mathrm{c}}]\)
Step-by-step Solution
Detailed explanation
The volume of required parallelepiped
\(\begin{aligned}
& =(\bar{a}+\bar{b}) \cdot[(\bar{b}+\bar{c}) \times(\bar{c}+\bar{a})] \\
& =(\bar{a}+\bar{b}) \cdot[(\bar{b} \times \bar{c})+(\bar{b} \times \bar{a})+(\bar{c} \times \bar{c})+(\bar{c} \times \bar{a})] \\
& =[\bar{a} \cdot(\bar{b} \times \bar{c})]+[\bar{a} \cdot(\bar{b} \times \bar{a})]+0+[\bar{a} \times(\bar{c} \times \bar{a})] \\
& +[\bar{b} \cdot(\bar{b} \times \bar{a})]+0+[\bar{b} \cdot(\bar{c} \times \bar{a})] \\
& =[\bar{a} \cdot(\bar{b} \times \bar{c})]+0+0+0+0+0+0+[\bar{b} \cdot(\bar{c} \times \bar{a})] \\
& =2 \bar{a} \cdot(\bar{b} \times \bar{c})
\end{aligned}\)
\(\begin{aligned}
& =(\bar{a}+\bar{b}) \cdot[(\bar{b}+\bar{c}) \times(\bar{c}+\bar{a})] \\
& =(\bar{a}+\bar{b}) \cdot[(\bar{b} \times \bar{c})+(\bar{b} \times \bar{a})+(\bar{c} \times \bar{c})+(\bar{c} \times \bar{a})] \\
& =[\bar{a} \cdot(\bar{b} \times \bar{c})]+[\bar{a} \cdot(\bar{b} \times \bar{a})]+0+[\bar{a} \times(\bar{c} \times \bar{a})] \\
& +[\bar{b} \cdot(\bar{b} \times \bar{a})]+0+[\bar{b} \cdot(\bar{c} \times \bar{a})] \\
& =[\bar{a} \cdot(\bar{b} \times \bar{c})]+0+0+0+0+0+0+[\bar{b} \cdot(\bar{c} \times \bar{a})] \\
& =2 \bar{a} \cdot(\bar{b} \times \bar{c})
\end{aligned}\)
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