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MHT CET · Maths · Trigonometric Ratios & Identities

If \(\mathrm{A}+\mathrm{B}=\frac{\pi}{2}\) then the maximum value of \(\cos \mathrm{A} \cdot \cos \mathrm{B}\) is

  1. A \(\frac{1}{\sqrt{2}}\)
  2. B \(\frac{1}{2}\)
  3. C \(-\frac{1}{2}\)
  4. D \(-\frac{1}{\sqrt{2}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{B}=\frac{\pi}{2}-\mathrm{A}\) \(\cos \mathrm{A} \cdot \cos \mathrm{B} = \cos \mathrm{A} \cdot \cos \left(\frac{\pi}{2}-\mathrm{A}\right)\)