MHT CET · Maths · Matrices
If \(\mathrm{A}=\left[\begin{array}{rr}1 & 2 \\ -1 & 4\end{array}\right]\) and \(\mathrm{A}^{-1}=\alpha \mathrm{I}+\beta \mathrm{A}\)
\(\alpha, \beta \in \mathrm{R}\) where I is the identity matrix of order 2 , then \(4(\alpha+\beta)=\)
- A \(\frac{8}{3}\)
- B \(\frac{2}{3}\)
- C \(\frac{10}{3}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{8}{3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{det}(\mathrm{A}) = (1)(4) - (2)(-1) = 6\) \(\mathrm{A}^{-1} = \frac{1}{6} \left[\begin{array}{rr}4 & -2 \\ 1 & 1\end{array}\right] = \left[\begin{array}{rr}2/3 & -1/3 \\ 1/6 & 1/6\end{array}\right]\)
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