MHT CET · Maths · Determinants
If \(A\left[\begin{array}{lll}3 & 2 & 4 \\ 1 & 2 & 1 \\ 3 & 2 & 6\end{array}\right]\) and \(\mathrm{A}_{\mathrm{ij}}\) are cofactors of the elements \(\mathrm{a}_{\mathrm{ij}}\) of \(\mathrm{A}\), then \(a_{11} A_{11}+a_{12} A_{12}+a_{13} A_{13}\) is equal to
- A 8
- B 6
- C 4
- D 0
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & a_{11} A_{11}+a_{12} A_{12}+a_{13} A_{13}=|A| \\ & \therefore|A|=\left|\begin{array}{lll}3 & 2 & 4 \\ 1 & 2 & 1 \\ 3 & 2 & 6\end{array}\right| \\ & =3(12-2)-2(6-3)+4(2-6)=30-6-16=8\end{aligned}\)
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