MHT CET · Maths · Matrices
If \(A=\left[\begin{array}{lll}3 & 2 & 4 \\ 1 & 2 & 1 \\ 3 & 2 & 6\end{array}\right]\) and \(A_{i j}\) are the cofactors of \(a_{\tilde{y}}\),
then \(a_{11} A_{11}+a_{12} A_{12}+a_{13} A_{13}\) is equal to
- A 8
- B 6
- C 4
- D 0
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
\(\begin{aligned} a_{11} A_{11}+a_{12} A_{12} &+a_{13} A_{13} \\ &=3\left|\begin{array}{ll}2 & 1 \\ 2 & 6\end{array}\right|-2\left|\begin{array}{ll}1 & 1 \\ 3 & 6\end{array}\right|+4\left|\begin{array}{ll}1 & 2 \\ 3 & 2\end{array}\right| \\ &=3(12-2)-2(6-3)+4(2-6) \\ &=30-6-16 \\ &=8 \end{aligned}\)
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