MHT CET · Maths · Matrices
If \(A=\left[\begin{array}{ccc}0 & 0 & -1 \\ 0 & -1 & 0 \\ -1 & 0 & 0\end{array}\right]\), then
- A \(A\) is not invertible
- B \(A=A^{-1}\)
- C \(A^{-1}=2 A\)
- D \(A^{-1}=I\)
Answer & Solution
Correct Answer
(B) \(A=A^{-1}\)
Step-by-step Solution
Detailed explanation
Here \(|\mathrm{A}|=-1(-1)=1\)
and \(\quad A^{-1}=\left[\begin{array}{ccc}0 & 0 & -1 \\ 0 & -1 & 0 \\ -1 & 0 & 0\end{array}\right]=A\)
and \(\quad A^{-1}=\left[\begin{array}{ccc}0 & 0 & -1 \\ 0 & -1 & 0 \\ -1 & 0 & 0\end{array}\right]=A\)
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