MHT CET · Maths · Vector Algebra
If \(\bar{a}\) and \(\overline{\mathrm{b}}\) are unit vectors such that \(|\bar{a}+\overline{\mathrm{b}}|=\sqrt{3}\), then the angle between \(\bar{a}\) and \(\overline{\mathrm{b}}\) is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{\pi}{4}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(|\bar{a}+\overline{b}|^2 = |\bar{a}|^2 + |\overline{b}|^2 + 2|\bar{a}||\overline{b}|\cos\theta\) \((\sqrt{3})^2 = 1^2 + 1^2 + 2(1)(1)\cos\theta\)
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