MHT CET · Maths · Vector Algebra
If \(\bar{a}\) and \(\bar{b}\) are unit vectors and \(\theta\) is the angle between them, then \(\bar{a}+\bar{b}\) is a unit vector when \(\theta\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{2 \pi}{3}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 \pi}{3}\)
Step-by-step Solution
Detailed explanation
\(|\bar{a}+\bar{b}|^2 = |\bar{a}|^2 + |\bar{b}|^2 + 2|\bar{a}||\bar{b}|\cos\theta\) \(1^2 = 1^2 + 1^2 + 2(1)(1)\cos\theta\)
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