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MHT CET · Maths · Vector Algebra

If \(\bar{a}\) and \(\bar{b}\) are two vectors such that \(|\vec{a}|=|\vec{b}|=\sqrt{2}\) with \(\vec{a} \cdot \vec{b}=-1\), then the angle between \(\bar{a}\) and \(\bar{b}\) is

  1. A \(\frac{3 \pi}{4}\)
  2. B \(\frac{5 \pi}{6}\)
  3. C \(\frac{5 \pi}{9}\)
  4. D \(\frac{2 \pi}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{2 \pi}{3}\)

Step-by-step Solution

Detailed explanation

\(\theta=\cos ^{-1}\left(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}\right)=\cos ^{-1}\left(\frac{-1}{\sqrt{2} \sqrt{2}}\right)=\cos ^{-1}\left(\frac{-1}{2}\right)=\frac{2 \pi}{3}\)
From MHT CET
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