MHT CET · Maths · Matrices
If \(A\) and \(B\) are non-singular matrices of order 2 such that \((\mathrm{AB})^{-1}=\frac{1}{6}\left[\begin{array}{cc}-7 & -3 \\ 2 & 3\end{array}\right]\) and \(\mathrm{A}^{-1}=\frac{1}{3}\left[\begin{array}{cc}4 & 3 \\ -1 & 0\end{array}\right]\) then \(\mathrm{B}^{-1}=\)
- A \(\frac{1}{2}\left[\begin{array}{cc}2 & 3 \\ 1 & -1\end{array}\right]\)
- B \(\frac{1}{2}\left[\begin{array}{ll}3 & 1 \\ 2 & 4\end{array}\right]\)
- C \(\frac{1}{2}\left[\begin{array}{cc}-1 & 3 \\ 1 & 2\end{array}\right]\)
- D \(\frac{1}{6}\left[\begin{array}{ll}1 & 1 \\ 2 & 3\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\left[\begin{array}{cc}-1 & 3 \\ 1 & 2\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\((\mathrm{AB})^{-1} = \mathrm{B}^{-1}\mathrm{A}^{-1}\) \(\mathrm{B}^{-1} = (\mathrm{AB})^{-1}\mathrm{A}\)
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