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MHT CET · Maths · Determinants

If \(\mathrm{A}=\left[\mathrm{a}_{\mathrm{ij}}\right]_{3 \times 3}=\left[\begin{array}{lll}1 & 2 & 3 \\ 1 & 1 & 5 \\ 2 & 4 & 7\end{array}\right]\) and \(\mathrm{Aij}\) is a cofactor of \(\mathrm{a}_{\mathrm{ij}}\), then \(a_{11} A_{21}+a_{12} A_{22}+a_{13} A_{23}\) is equal to

  1. A \(-1\)
  2. B \(2\)
  3. C \(0\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0\)

Step-by-step Solution

Detailed explanation

If we multiply elements of one row to the corresponding cofactors of another row and add them then we get zero hence,
\(a_{11} A_{21}+a_{12} A_{22}+a_{13} A_{23}=0\)