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MHT CET · Maths · Determinants

If \(A=\left[a_{i j}\right]_{3 \times 3}=\left[\begin{array}{lll}3 & 2 & 4 \\ 1 & 4 & 1 \\ 2 & 6 & 3\end{array}\right]\) and \(A_{i j}\) is a cofactor of \(a_{i j}\), then the value of \(a_{21} A_{21}+a_{22} A_{22}+a_{23} A_{23}\) is equal to

  1. A 18
  2. B 8
  3. C -8
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(B) 8

Step-by-step Solution

Detailed explanation

\(a_{21} A_{21}, a_{22} A_{22}+a_{23} A_{23}=|A|=3 \times(12-6)-2(3-2)+4(6-8)=8\)