MHT CET · Maths · Vector Algebra
If \(\bar{a}=\hat{\imath}+5 \hat{k}, \bar{b}=2 \hat{\imath}+3 \hat{k}, \bar{c}=4 \hat{\imath}-\hat{\jmath}+2 \hat{k}\) and \(\bar{d}=\hat{\imath}-\hat{\jmath}\),
then \((\bar{c}-\bar{a}) \cdot(\bar{b} \times \bar{d})=\)
- A \(12\)
- B \(20\)
- C \(30\)
- D \(10\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(\bar{b} \times \bar{d}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 2 & 0 & 3 \\ 1 & -1 & 0\end{array}\right|=\hat{i}(3)-\hat{j}(0-3)+\hat{k}(-2)\)
\(\bar{b} \times \bar{d}=3 \hat{i}+3 \hat{j}-2 \hat{k}\)
and \(\bar{c}-\bar{a}=3 \hat{i}-\hat{j}-3 \hat{k}\)
then \((\bar{c}-\bar{a}) \cdot(\bar{b} \times \bar{d})=3(3)+(-1)(3)+(-3)(-2)\)
\(=9-3+6=12\)
\(\bar{b} \times \bar{d}=3 \hat{i}+3 \hat{j}-2 \hat{k}\)
and \(\bar{c}-\bar{a}=3 \hat{i}-\hat{j}-3 \hat{k}\)
then \((\bar{c}-\bar{a}) \cdot(\bar{b} \times \bar{d})=3(3)+(-1)(3)+(-3)(-2)\)
\(=9-3+6=12\)
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