MHT CET · Maths · Vector Algebra
If \(|\bar{a}|=3,|\bar{b}|=5\) and \(|\bar{c}|=7\) and \(\bar{a}+\bar{b}+\bar{c}=\overline{0}\), then the angle between \(\bar{a}\) and \(\bar{b}\) is
- A \(\frac{\pi}{4}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \vec{a}+\vec{b}+\vec{c}=0 \\ & \Rightarrow \vec{a}+\vec{b}=-\vec{c} \\ & \Rightarrow|\vec{a}+\vec{b}|^2=|\vec{c}|^2 \\ & \Rightarrow|\vec{a}|^2+|\vec{b}|^2+2|\vec{a}||\vec{b}| \cos \theta=|\vec{c}|^2 \\ & \Rightarrow 3^2+5^2+2 \times 3 \times 5 \cos \theta=7^2 \\ & \Rightarrow \cos \theta=\frac{15}{30}=\frac{1}{2}=\cos \frac{\pi}{3} \\ & \Rightarrow \theta=\frac{\pi}{3}\end{aligned}\)
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