MHT CET · Maths · Vector Algebra
If \(\overline{\mathrm{a}}=2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-4 \hat{\mathrm{k}}\) and \(\overline{\mathrm{b}}=\hat{\mathrm{i}}-\hat{\mathrm{j}}-\hat{\mathrm{k}}\), then the projection of \(\bar{b}\) in the direction of \(\bar{a}\) is
- A \(\frac{1}{\sqrt{29}}\)
- B \(\frac{2}{\sqrt{3}}\)
- C \(\frac{5}{\sqrt{3}}\)
- D \(\frac{3}{\sqrt{29}}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{\sqrt{29}}\)
Step-by-step Solution
Detailed explanation
Projection of \(\overline{\mathrm{b}}\) in the direction of \(\overline{\mathrm{a}}=\frac{\overline{\mathrm{a}} \cdot \overline{\mathrm{b}}}{|\overline{\mathrm{a}}|}\)
\(=\frac{(2 \hat{i}+3 \hat{j}-4 \hat{k}) \cdot(\hat{i}-\hat{j}-\hat{k})}{\sqrt{2^2+3^2+(-4)^2}}\)
\(=\frac{2-3+4}{\sqrt{4+9+16}}=\frac{3}{\sqrt{29}}\)
\(=\frac{(2 \hat{i}+3 \hat{j}-4 \hat{k}) \cdot(\hat{i}-\hat{j}-\hat{k})}{\sqrt{2^2+3^2+(-4)^2}}\)
\(=\frac{2-3+4}{\sqrt{4+9+16}}=\frac{3}{\sqrt{29}}\)
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