MHT CET · Maths · Vector Algebra
If \(\bar{a}=2 \hat{i}+2 \hat{j}+3 \hat{k}, \quad \bar{b}=-\hat{i}+2 \hat{j}+\hat{k}\) and \(\bar{c}=3 \hat{i}+\hat{j}\) are the vectors such that \(\bar{a}+\lambda \bar{b}\) is perpendicular to \(\bar{c}\), then value of \(\lambda\) is
- A 6
- B -6
- C 8
- D -8
Answer & Solution
Correct Answer
(C) 8
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \overline{\mathrm{a}}+\lambda \overline{\mathrm{b}}=2 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}+\lambda(-\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}}) \\ & \quad=(2-\lambda) \hat{\mathrm{i}}+(2+2 \lambda) \hat{\mathrm{j}}+(3+\lambda) \hat{\mathrm{k}} \\ & (\overline{\mathrm{a}}+\lambda \overline{\mathrm{b}}) \cdot \overline{\mathrm{c}}=0 \\ & \Rightarrow(2-\lambda)(3)+(2+2 \lambda)(1)+(3+\lambda)(0)=0 \\ & \Rightarrow 8-\lambda=0 \\ & \Rightarrow \lambda=8\end{aligned}\)
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