MHT CET · Maths · Straight Lines
If \((a,-2 a), a>0\) is the midpoint of a line segment intercepted between the co-ordinate axes, then the equation of the line is
- A \(x-2 y+4 a=0\)
- B \(2 x-y=4 a\)
- C \(x-2 y=5 a\)
- D \(2x-y+4 a=0\)
Answer & Solution
Correct Answer
(B) \(2 x-y=4 a\)
Step-by-step Solution
Detailed explanation
Given point \((a,-2 a)\) is the midpoint of the intercepts.
Let Points \(A, B, M\) be as shown in figure.
Hence the intercept points are \((2 \mathrm{a}, 0)\) and \((0,-4 \mathrm{a})\)
Equation of line from intercept in intercept form.
\(\frac{x}{2 a}+\frac{y}{-4 a}=1 \Rightarrow 2 x-y=4 a\)
Let Points \(A, B, M\) be as shown in figure.
Hence the intercept points are \((2 \mathrm{a}, 0)\) and \((0,-4 \mathrm{a})\)
Equation of line from intercept in intercept form.
\(\frac{x}{2 a}+\frac{y}{-4 a}=1 \Rightarrow 2 x-y=4 a\)
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