MHT CET · Maths · Vector Algebra
If \(\overline{\mathrm{a}}=\frac{1}{\sqrt{10}}(3 \hat{i}+\hat{\mathrm{k}}), \overline{\mathrm{b}}=\frac{1}{7}(2 \hat{i}+3 \hat{\mathrm{j}}-6 \hat{\mathrm{k}})\), then the value of \((\overline{\mathrm{a}}-2 \overline{\mathrm{~b}}) \cdot\{(\overline{\mathrm{a}} \times \overline{\mathrm{b}}) \times(2 \overline{\mathrm{a}}+\overline{\mathrm{b}})\}\) is
- A 5
- B -5
- C 3
- D -3
Answer & Solution
Correct Answer
(B) -5
Step-by-step Solution
Detailed explanation
\(|\overline{\mathrm{a}}|^2 = \left(\frac{1}{\sqrt{10}}\right)^2 (3^2+1^2) = \frac{1}{10}(9+1) = 1\) \(|\overline{\mathrm{b}}|^2 = \left(\frac{1}{7}\right)^2 (2^2+3^2+(-6)^2) = \frac{1}{49}(4+9+36) = 1\)
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