MHT CET · Maths · Vector Algebra
If \(\bar{a}=\frac{1}{\sqrt{10}}(3 \hat{i}+\hat{\mathrm{k}})\) and \(\overline{\mathrm{b}}=\frac{1}{7}(2 \hat{i}+3 \hat{\mathrm{j}}-6 \hat{\mathrm{k}})\) then the value of \((2 \bar{a}-\overline{\mathrm{b}}) \cdot((\bar{a} \times \overline{\mathrm{b}}) \times(\bar{a}+2 \overline{\mathrm{~b}}))=\)
- A 3
- B -3
- C 5
- D -5
Answer & Solution
Correct Answer
(D) -5
Step-by-step Solution
Detailed explanation
\( |\bar{a}|^2 = \left(\frac{1}{\sqrt{10}}\right)^2 (3^2+1^2) = \frac{1}{10}(9+1) = 1 \) \( |\overline{\mathrm{b}}|^2 = \left(\frac{1}{7}\right)^2 (2^2+3^2+(-6)^2) = \frac{1}{49}(4+9+36) = 1 \)
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