MHT CET · Maths · Straight Lines
If \(4 a b=3 h^2\), then the ratio of the slope of lines represented by \(a x^2+2 h x y+b y^2=0\) is
- A \(\sqrt{3}: 1\)
- B \(1: \sqrt{3}\)
- C \(1: 3\)
- D \(3: 1\)
Answer & Solution
Correct Answer
(C) \(1: 3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \text {Here, } m_1+m_2=\frac{-2 h}{b} ...(i) \\
& \text { and } \mathrm{m}_1 \mathrm{~m}_2=\frac{\mathrm{a}}{\mathrm{~b}}. \\
& \therefore \quad\left(m_1-m_2\right)^2=\left(m_1+m_2\right)^2-4 m_1 m_2 \\
& =\frac{4 h^2-4 a b}{b^2} \\
& =\frac{4 h^2-3 h^2}{b^2} \ldots\left[\because 4 a b=3 h^2 \text { (given) }\right] \\
& =\frac{h^2}{b^2}
\end{aligned}\)
\(\therefore \quad \mathrm{m}_1-\mathrm{m}_2=\frac{\mathrm{h}}{\mathrm{~b}}...(ii)\)
On solving (i) and (ii), we get
\(\begin{aligned}
& \quad m_1=\frac{-h}{2 b} \text { and } m_2=\frac{-3 h}{2 b} \\
& \therefore \quad m_1: m_2=1: 3
\end{aligned}\)
& \text {Here, } m_1+m_2=\frac{-2 h}{b} ...(i) \\
& \text { and } \mathrm{m}_1 \mathrm{~m}_2=\frac{\mathrm{a}}{\mathrm{~b}}. \\
& \therefore \quad\left(m_1-m_2\right)^2=\left(m_1+m_2\right)^2-4 m_1 m_2 \\
& =\frac{4 h^2-4 a b}{b^2} \\
& =\frac{4 h^2-3 h^2}{b^2} \ldots\left[\because 4 a b=3 h^2 \text { (given) }\right] \\
& =\frac{h^2}{b^2}
\end{aligned}\)
\(\therefore \quad \mathrm{m}_1-\mathrm{m}_2=\frac{\mathrm{h}}{\mathrm{~b}}...(ii)\)
On solving (i) and (ii), we get
\(\begin{aligned}
& \quad m_1=\frac{-h}{2 b} \text { and } m_2=\frac{-3 h}{2 b} \\
& \therefore \quad m_1: m_2=1: 3
\end{aligned}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- \(\int_0^{\pi / 2} \log \left(\frac{4+3 \sin x}{4+3 \cos x}\right) d x=\)MHT CET 2021 Hard
- The equation of the line passing through the point \((-1,3,-2)\) and perpendicular to each of the lines \(\frac{x}{1}=\frac{y}{2}=\frac{z}{3}\) and \(\frac{x+2}{-3}=\frac{y-1}{2}=\frac{z+1}{5}\), isMHT CET 2024 Medium
- Consider the statement " \(\mathrm{P}(n): n^2-n+37\) is prime." then, which one of the following is true?MHT CET 2022 Easy
- \(\int_0^1 \cos ^{-1} x d x=\)MHT CET 2023 Medium
- \(\operatorname{Cos}\left(36^{\circ}-\mathrm{A}\right) \cos \left(36^{\circ}+\mathrm{A}\right)+\cos \left(54^{\circ}+\mathrm{A}\right) \cos \left(54^{\circ}-\mathrm{A}\right)=\)MHT CET 2020 Easy
- If \(a>0\) and \(z=\frac{(1+i)^2}{a+i},(i=\sqrt{-1})\) has magnitude \(\frac{2}{\sqrt{5}}\), then \(\bar{z}\) is equal toMHT CET 2023 Medium
More PYQs from MHT CET
- Two small identical metal balls are equally charged and placed at a fixed distance away from each other. They experience the electrostatic force ' \(F\) ' A similar uncharged ball after touching one of them is placed at the middle point between the two balls. The force experienced by this ball isMHT CET 2022 Medium
- Identify the reactant, reagent and condition of Kolbe's reaction from following.MHT CET 2021 Medium
- Bicuspid and tricuspid valves are attached with inelastic fibres to the papillary muscles in the lumen of ventricles. These fibres are __________ .MHT CET 2024 Medium
- What is the total number of -OH groups present in ribonucleoside?MHT CET 2025 Easy
- In a chemical reaction, sum of formula weight of all reactants is 274 u and atom economy is \(50 \%\), calculate formula weight of desired product?MHT CET 2025 Easy
- The foot of the perpendicular from the point \((1,2,3)\) on the line \(\overline{\mathrm{r}}=(6 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}+7 \hat{\mathrm{k}})+\lambda(3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-2 \hat{\mathrm{k}})\) has the co-ordinatesMHT CET 2023 Easy