MHT CET · Maths · Complex Number
If \((3 x+2)-(5 y-3) \mathrm{i}\) and \((6 x+3)+(2 y-4) \mathrm{i}\) are conjugates of each other, then the value of \(\frac{x-y}{x+y}\) is (where \(\mathrm{i}=\sqrt{-1}, x, y \in \mathrm{R}\) )
- A \(-1\)
- B 0
- C 1
- D 2
Answer & Solution
Correct Answer
(B) 0
Step-by-step Solution
Detailed explanation
\((3 x+2)-(5 y-3) \mathrm{i}\) and \((6 x+3)+(2 y-4) \mathrm{i}\) are conjugates of each other.
\(\Rightarrow 3 x+2=6 x+3\) and \(5 y-3=2 y-4\)
\(\Rightarrow 3 x=-1\) and \(3 y=-1\)
\(\Rightarrow x=-\frac{1}{3}\) and \(y=-\frac{1}{3}\)
\(\therefore \frac{x-y}{x+y}=0\)
\(\Rightarrow 3 x+2=6 x+3\) and \(5 y-3=2 y-4\)
\(\Rightarrow 3 x=-1\) and \(3 y=-1\)
\(\Rightarrow x=-\frac{1}{3}\) and \(y=-\frac{1}{3}\)
\(\therefore \frac{x-y}{x+y}=0\)
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