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MHT CET · Maths · Indefinite Integration

If \(\int \frac{2 x+3}{(x-1)\left(x^2+1\right)} \mathrm{d} x=\log _e\left\{(x-1)^{\frac{5}{2}}\left(x^2+1\right)^a\right\}-\frac{1}{2} \tan ^{-1} x+\mathrm{A}\) where \(A\) is an arbitrary constant, then the value of \(a\) is

  1. A \(\frac{5}{4}\)
  2. B \(-\frac{5}{4}\)
  3. C \(-\frac{5}{3}\)
  4. D \(-\frac{5}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\frac{5}{4}\)

Step-by-step Solution

Detailed explanation

Decompose integrand: \( \frac{2 x+3}{(x-1)\left(x^2+1\right)} = \frac{5/2}{x-1} - \frac{5x/2}{x^2+1} - \frac{1/2}{x^2+1} \) Integrate: \( \int \left( \frac{5/2}{x-1} - \frac{5x/2}{x^2+1} - \frac{1/2}{x^2+1} \right) \mathrm{d} x = \frac{5}{2} \log_e(x-1) - \frac{5}{4} \log_e(x^2+1) - \frac{1}{2} \tan^{-1}x + C \)
From MHT CET
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