MHT CET · Maths · Inverse Trigonometric Functions
If \(\tan ^{-1}\left(\frac{x}{2}\right)+\tan ^{-1}\left(\frac{y}{2}\right)+\tan ^{-1}\left(\frac{z}{2}\right)=\frac{\pi}{2}\) then \(x y+y z+z x=\)
- A \(0\)
- B \(2\)
- C \(-1\)
- D \(4\)
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
Let \( A=\tan ^{-1}\left(\frac{x}{2}\right) \), \( B=\tan ^{-1}\left(\frac{y}{2}\right) \), \( C=\tan ^{-1}\left(\frac{z}{2}\right) \). Given \( A+B+C=\frac{\pi}{2} \).
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