MHT CET · Maths · Indefinite Integration
If \(\int \frac{1+\mathrm{x}^2}{1+\mathrm{x}^4} \mathrm{dx}=\frac{1}{\sqrt{2}} \tan ^{-1}\left[\frac{\mathrm{f}(\mathrm{x})}{\sqrt{2}}\right]+\mathrm{c}\), then \(\mathrm{f}(\mathrm{x})=\)
- A \(x+\frac{1}{x^2}\)
- B \(x-\frac{1}{x^2}\)
- C \(x+\frac{2}{x}\)
- D \(x-\frac{2}{x}\)
Answer & Solution
Correct Answer
(D) \(x-\frac{2}{x}\)
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