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MHT CET · Maths · Indefinite Integration

If \(\int \frac{1+\mathrm{x}^2}{1+\mathrm{x}^4} \mathrm{dx}=\frac{1}{\sqrt{2}} \tan ^{-1}\left[\frac{\mathrm{f}(\mathrm{x})}{\sqrt{2}}\right]+\mathrm{c}\), then \(\mathrm{f}(\mathrm{x})=\)

  1. A \(x+\frac{1}{x^2}\)
  2. B \(x-\frac{1}{x^2}\)
  3. C \(x+\frac{2}{x}\)
  4. D \(x-\frac{2}{x}\)
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Correct Answer

(D) \(x-\frac{2}{x}\)

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