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MHT CET · Maths · Inverse Trigonometric Functions

If \(\sin \left(\cot ^{-1}(x+1)\right)=\cos \left(\tan ^{-1} x\right)\) then considering positive square roots, \(x\) has the value \(\qquad\)

  1. A 0
  2. B \(\frac{9}{4}\)
  3. C \(\frac{1}{2}\)
  4. D \(-\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \sin \left(\cot ^{-1}(x+1)\right)=\cos \left(\tan ^{-1} x\right) \\ & \sin \left[\sin ^{-1} \frac{1}{\sqrt{x^2+2 x+2}}\right]=\cos \left[\cos ^{-1} \frac{1}{\sqrt{1+x^2}}\right] \\ & \frac{1}{\sqrt{x^2+2 x+2}}=\frac{1}{\sqrt{1+x^2}} \\ & \Rightarrow \sqrt{1+x^2}=\sqrt{x^2+2 x+2} \\ & \Rightarrow 1+x^2=x^2+2 x+2 \\ & \Rightarrow 2 x+1=0 \\ & \Rightarrow x=\frac{-1}{2}\end{aligned}\)
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