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MHT CET · Maths · Complex Number

If \(\left(\frac{1-i}{1+i}\right)^{100}=a+i b\), where, \(a b \in R\) and \(i=\sqrt{-1}\), then \((a, b)\) is equal to

  1. A \((1,0)\)
  2. B \((0,1)\)
  3. C \((-1,2)\)
  4. D \((2,-1)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((1,0)\)

Step-by-step Solution

Detailed explanation

\(\left(\frac{1-i}{1+i}\right)^{100}=\left\{\frac{(1-i)(1-i)}{(1+i)(1-i)}\right\}^{100}=\left(\frac{1-1-2 i}{1+1}\right)^{100}\) \(=(-i)^{100}=1=a+i b\)
\(\Rightarrow a=1 \text { and } b=0\)