MHT CET · Maths · Inverse Trigonometric Functions
If \(\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1\), then the value of \(x\) is
- A \(\frac{1}{5}\)
- B \(1\)
- C \(0\)
- D \(-\frac{1}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{5}\)
Step-by-step Solution
Detailed explanation
\(\sin^{-1} \frac{1}{5}+\cos^{-1} x = \sin^{-1}(1)\) \(\sin^{-1} \frac{1}{5}+\cos^{-1} x = \frac{\pi}{2}\)
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