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MHT CET · Maths · Trigonometric Equations

If \(\frac{1-\tan \theta}{1+\tan \theta}=\frac{1}{\sqrt{3}}\), where \(\theta \in\left(0, \frac{\pi}{2}\right)\), then \(\theta=\)

  1. A \(\frac{\pi}{12}\)
  2. B \(\frac{\pi}{4}\)
  3. C \(\frac{\pi}{6}\)
  4. D \(\frac{\pi}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\pi}{12}\)

Step-by-step Solution

Detailed explanation

Given \(\frac{1-\tan \theta}{1+\tan \theta}=\frac{1}{\sqrt{3}}\)
\(\therefore \tan \left(\frac{\pi}{4}-\theta\right)=\frac{1}{\sqrt{3}}\)
Comparing with \(\tan \frac{\pi}{6}=\frac{1}{\sqrt{3}}\), we write
\(\frac{\pi}{4}-\theta=\frac{\pi}{6} \)
\( \therefore \theta=\frac{\pi}{4}-\frac{\pi}{6}=\frac{\pi}{12}\)