MHT CET · Maths · Inverse Trigonometric Functions
If \(0 \leqslant \cos ^{-1} x \leqslant \pi\) and \(\frac{-\pi}{2} \leqslant \sin ^{-1} x \leqslant \frac{\pi}{2}\), then at \(x=\frac{1}{5}\) the value of \(\cos \left(2 \cos ^{-1} x+\sin ^{-1} x\right)\) is
- A \(-\sqrt{\frac{24}{25}}\)
- B \(\sqrt{\frac{24}{25}}\)
- C \(\frac{\sqrt{24}}{25}\)
- D \(\frac{-\sqrt{24}}{25}\)
Answer & Solution
Correct Answer
(A) \(-\sqrt{\frac{24}{25}}\)
Step-by-step Solution
Detailed explanation
\(\cos \left(2 \cos ^{-1} x+\sin ^{-1} x\right) = \cos \left(\cos ^{-1} x + (\cos ^{-1} x+\sin ^{-1} x)\right)\) \(= \cos \left(\cos ^{-1} x + \frac{\pi}{2}\right)\)
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