MHT CET · Maths · Statistics
Given that total of 16 values is 528 and sum of the squares of deviation from 33 is 9158 . The variance is
- A 562.73
- B 570.375
- C 574.375
- D 572.375
Answer & Solution
Correct Answer
(D) 572.375
Step-by-step Solution
Detailed explanation
We have \(\mathrm{n}=16, \Sigma \mathrm{x}_{\mathrm{i}}=528\), and \(\frac{528}{16}=33\) \(\Rightarrow \overline{\mathrm{x}}=33\) and \(\Sigma\left(\mathrm{x}_{\mathrm{i}}-\overline{\mathrm{x}}\right)^2=9158\)
Variance \(=\frac{1}{\mathrm{n}} \Sigma\left(\mathrm{x}_{\mathrm{i}}-\overline{\mathrm{x}}\right)^2=\frac{9158}{16}=527.375\)
Variance \(=\frac{1}{\mathrm{n}} \Sigma\left(\mathrm{x}_{\mathrm{i}}-\overline{\mathrm{x}}\right)^2=\frac{9158}{16}=527.375\)
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