MHT CET · Maths · Application of Derivatives

Function \(\mathrm{f}(\mathrm{x})=\mathrm{e}^{-1 / \mathrm{x}}\) is strictly increasing for all \(\mathrm{x}\) where

A \(\mathrm{x}\) is only positive real number
B \(\mathrm{x}\) is only negative real number
C \(\mathrm{x}\) is a real number
D \(\mathrm{x}\) is a non - zero real number

Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{x}\) is a non - zero real number

Step-by-step Solution

Detailed explanation

\(
\begin{aligned}
& f(x)=e^{-\frac{1}{x}} \\
& f^{\prime}(x)=e^{-\frac{1}{x}}(-1)\left(\frac{-1}{x^2}\right)=\frac{1}{x^2 e^{\frac{1}{x}}}
\end{aligned}
\)
When \(\mathrm{f}^{\prime}(\mathrm{x})>0, \mathrm{x}^2 \mathrm{e}^{\frac{1}{\mathrm{x}}}>0\) and \(\mathrm{x} \neq 0\)
Now \(\mathrm{x}^2>0\) and \(\mathrm{e}^{\frac{1}{\mathrm{x}}}>0\) for \(\forall \mathrm{x} \in \mathrm{R}\)
Hence \(f(x)\) is an increasing function for \(\forall x\), except \(x=0\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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