MHT CET · Maths · Probability
From a lot of 20 baskets, which includes 6 defective baskets, a sample of 2 baskets is drawn at random one by one without replacement. The expected value of number of defective basket is
- A \(0.6\)
- B \(0.06\)
- C \(0.006\)
- D \(1.07\)
Answer & Solution
Correct Answer
(A) \(0.6\)
Step-by-step Solution
Detailed explanation
Let \(\mathrm{X}\) denotes the number of defective baskets.
\(\therefore\) Possible values of \(\mathrm{X}\) are \(0,1,2\).
Now, selection of baskets is done without replacement, we get
\(P(X=0)=\frac{14}{20} \times \frac{13}{19}=\frac{182}{380}\)
\(\therefore\) Possible values of \(\mathrm{X}\) are \(0,1,2\).
Now, selection of baskets is done without replacement, we get
\(P(X=0)=\frac{14}{20} \times \frac{13}{19}=\frac{182}{380}\)
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