MHT CET · Maths · Differential Equations
Form the differential equation of all family of lines \(y=m x+\frac{4}{m}\) by eliminating the arbitrary constant ' \(m^{\prime}\) ' is
- A \(\frac{d^{2} y}{d x^{2}}=0\)
- B \(x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}+4=0\)
- C \(x\left(\frac{d y}{d x}\right)^{2}+y \frac{d y}{d x}+4=0\)
- D \(\frac{d y}{d x}=0\)
Answer & Solution
Correct Answer
(B) \(x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}+4=0\)
Step-by-step Solution
Detailed explanation
\(y=m x+\frac{4}{m}\)
\(\therefore \quad \frac{d y}{d x}=m\)
From Eq. (i), we get
\(
\begin{aligned}
y &=x\left(\frac{d y}{d x}\right)+\frac{4}{(d y / d x)} \\
\Rightarrow & y\left(\frac{d y}{d x}\right)=x\left(\frac{d y}{d x}\right)^{2}+4 \\
\Rightarrow & x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}+4=0
\end{aligned}
\)
Which is the required differential equation.
\(\therefore \quad \frac{d y}{d x}=m\)
From Eq. (i), we get
\(
\begin{aligned}
y &=x\left(\frac{d y}{d x}\right)+\frac{4}{(d y / d x)} \\
\Rightarrow & y\left(\frac{d y}{d x}\right)=x\left(\frac{d y}{d x}\right)^{2}+4 \\
\Rightarrow & x\left(\frac{d y}{d x}\right)^{2}-y \frac{d y}{d x}+4=0
\end{aligned}
\)
Which is the required differential equation.
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