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MHT CET · Maths · Differentiation

For \(\mathrm{n} \in \mathbb{N}\) if \(\mathrm{y}=a x^{\mathrm{n}+1}+\mathrm{b} x^{-\mathrm{n}}\), then \(x^2 \frac{\mathrm{~d}^2 \mathrm{y}}{\mathrm{d} x^2}=\)

  1. A \(n(n-1) y\)
  2. B \((n-1) y\)
  3. C \(\mathrm{n}(\mathrm{n}+1) \mathrm{y}\)
  4. D \((\mathrm{n}+1) \mathrm{y}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{n}(\mathrm{n}+1) \mathrm{y}\)

Step-by-step Solution

Detailed explanation

\(\frac{\mathrm{d} \mathrm{y}}{\mathrm{d} x} = a(n+1)x^{n} - bnx^{-n-1}\) \(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{d} x^2} = an(n+1)x^{n-1} + bn(n+1)x^{-n-2}\)