MHT CET · Maths · Matrices
For an invertible matrix \(A\), if \(A(\operatorname{adj} A)=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right]\), then \(|A|=\)
- A -200
- B 200
- C -2
- D 20
Answer & Solution
Correct Answer
(D) 20
Step-by-step Solution
Detailed explanation
We have \(A (\operatorname{adj} A )=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right]\)
\(\therefore| A ||\operatorname{adj} A |=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right] \Rightarrow| A |\left(| A |^{2-1}\right)=\) \(400 \Rightarrow(|A|)^2=(20)^2\)
\(\Rightarrow| A |=20\)
\(\therefore| A ||\operatorname{adj} A |=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right] \Rightarrow| A |\left(| A |^{2-1}\right)=\) \(400 \Rightarrow(|A|)^2=(20)^2\)
\(\Rightarrow| A |=20\)
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