MHT CET · Maths · Functions
For a real number \(x,[x]\) denotes the greatest integer less than or equal to \(x\). Then the value of
\(\left[\frac{1}{2}\right]+\left[\frac{1}{2}+\frac{1}{100}\right]+\left[\frac{1}{2}+\frac{2}{100}\right]+\left[\frac{1}{2}+\frac{3}{100}\right]+\ldots \ldots \ldots \ldots .+\left[\frac{1}{2}+\frac{99}{100}\right]=\)
- A \(49\)
- B \(100\)
- C \(0\)
- D \(50\)
Answer & Solution
Correct Answer
(D) \(50\)
Step-by-step Solution
Detailed explanation
\(\left[\frac{1}{2}+\frac{k}{100}\right]=0 \text{ for } k=0, 1, \ldots, 49\) \(\left[\frac{1}{2}+\frac{k}{100}\right]=1 \text{ for } k=50, 51, \ldots, 99\)
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