MHT CET · Maths · Matrices
For a \(3 \times 3\) matrix A, if \(\mathrm{A}(\operatorname{adj} \mathrm{A})=\left[\begin{array}{ccc}-10 & 0 & 0 \\ 0 & -10 & 2 \\ 0 & 0 & -10\end{array}\right]\), then the value of determinant of \(\mathrm{A}\) is
- A 100
- B -1000
- C -10
- D 20
Answer & Solution
Correct Answer
(C) -10
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { We have }|\mathrm{A}(\operatorname{adj} \mathrm{A})|=\left[\begin{array}{ccc}-10 & 0 & 0 \\ 0 & -10 & 2 \\ 0 & 0 & -10\end{array}\right] \\ & \therefore|\mathrm{A}||\operatorname{adj} \mathrm{A}|=(-10)(100)=-1000 \\ & \therefore|\mathrm{A}||\mathrm{A}|^{3-1}=-1000 \Rightarrow|\mathrm{A}|^3=-1000 \Rightarrow|\mathrm{A}|=-10\end{aligned}\)
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