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MHT CET · Maths · Three Dimensional Geometry

Equation of the plane passing through the point \((1,2,3)\) and parallel to the plane \(2 x+3 y-4 z=0\)

  1. A \(2 x+3 y+4 z-8=0\)
  2. B \(2 x+3 y-4 z+4=0\)
  3. C \(2 x+3 y+4 z+4=0\)
  4. D \(2 x+3 y+4 z=20\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 x+3 y-4 z+4=0\)

Step-by-step Solution

Detailed explanation

Required plane passes through \((1,2,3)\) and is parallel to plane \(2 x+3 y-4 z=0\). Hence equation of required plane is
\(
2(x-1)+3(y-2)-4(z-3)=0 \Rightarrow 2 x+3 y~-\) \(4 z+4=0
\)
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