MHT CET · Maths · Indefinite Integration
\(\int \mathrm{e}^x \cos x \mathrm{~d} x=\)
- A \(\frac{\mathrm{e}^x \cos x}{2}+\sin x+\mathrm{c}, \quad\) where c is the constant of integration.
- B \(\frac{\mathrm{e}^x(\sin x+\cos x)}{2}+\mathrm{c}, \quad\) where c is the constant of integration.
- C \(\mathrm{e}^x\left(\frac{\cos x-\sin x}{2}\right)+\mathrm{c}, \quad\) where c is the constant of integration.
- D \(\mathrm{e}^x\left(\frac{\sin x-\cos x}{2}\right)+\mathrm{c}, \quad\) where c is the constant of integration.
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{e}^x(\sin x+\cos x)}{2}+\mathrm{c}, \quad\) where c is the constant of integration.
Step-by-step Solution
Detailed explanation
\(I = \int \mathrm{e}^x \cos x \mathrm{~d} x\) Using integration by parts: \(\int u \mathrm{~d} v = u v - \int v \mathrm{~d} u\)
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