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MHT CET · Maths · Indefinite Integration

\(\int e^{x} \frac{(x-1)}{x^{2}} d x\) is equal to

  1. A \(\frac{e^{x}}{x^{2}}+c\)
  2. B \(\frac{-e^{x}}{x^{2}}+c\)
  3. C \(\frac{e^{x}}{x}+c\)
  4. D \(\frac{-e^{x}}{x}+c\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{e^{x}}{x}+c\)

Step-by-step Solution

Detailed explanation

\(\int e^{x}\left(\frac{x-1}{x^{2}}\right) d x\)
\(\quad=\int e^{x}\left(\frac{1}{x}-\frac{1}{x^{2}}\right) d x\)
\(=\frac{e^{x}}{x}+c\left[\because \int e^{x}\left[f(x)+f^{\prime}(x)\right] d x=e^{x} f(x)+c\right]\)