MHT CET · Maths · Indefinite Integration
\(\int e^x\left(\frac{x-1}{x^2}\right) d x=\)
- A \(\frac{-e^x}{x^2}+c\)
- B \(\frac{-e^x}{x}+c\)
- C \(\frac{e^x}{x^2}+c\)
- D \(\frac{e^x}{x}+c\)
Answer & Solution
Correct Answer
(D) \(\frac{e^x}{x}+c\)
Step-by-step Solution
Detailed explanation
Let \(I=\int e^x\left(\frac{x-1}{x^2}\right) d x=\int e^x\left(\frac{1}{x}-\frac{1}{x^2}\right) d x=e^x\left(\frac{1}{x}\right)+c\)
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