MHT CET · Maths · Linear Programming
Dual of \((x+y)\left(x^{\prime} \cdot 1\right)\) is
- A \((x \cdot y)+\left(x^{\prime}+1\right)\)
- B \((x \cdot y)\left(x^{\prime}+1\right)\)
- C \((x \cdot y)+(x+1)\)
- D None of these
Answer & Solution
Correct Answer
(A) \((x \cdot y)+\left(x^{\prime}+1\right)\)
Step-by-step Solution
Detailed explanation
Dual of \((x+y) \cdot\left(x^{\prime} \cdot 1\right)\) is obtained by replacing
\(+\mathrm{by} \cdot \text { and } \cdot \mathrm{by}+\text { ie dual is }(x \cdot y)+\left(x^{\prime}+1\right) \text {.}\)
\(+\mathrm{by} \cdot \text { and } \cdot \mathrm{by}+\text { ie dual is }(x \cdot y)+\left(x^{\prime}+1\right) \text {.}\)
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