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MHT CET · Maths · Indefinite Integration

\(\int \frac{d x}{(x+2) \sqrt{x+1}}=\)

  1. A \(\tan ^{-1}(\sqrt{x+1})+c\)
  2. B \(2 \tan ^{-1}(\sqrt{x+1})+c\)
  3. C \(2 \tan ^{-1}(\sqrt{x+2})+c\)
  4. D \(\tan ^{-1}(\sqrt{x+2})+c\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \tan ^{-1}(\sqrt{x+1})+c\)

Step-by-step Solution

Detailed explanation

Let \(I=\int \frac{d x}{(x+2) \sqrt{x+1}}\)
Put \(\sqrt{x+1}=t \Rightarrow(x+1)=t^{2}\) and \(d x=2 t d t\)
\(\therefore I=\int \frac{2 t d t}{\left(t^{2}+1\right) t}\)
\(\quad=2 \int \frac{d t}{t^{2}+1}=2 \tan ^{-1} t+c=2 \tan ^{-1}(\sqrt{x+1})+c\)