MHT CET · Maths · Indefinite Integration
\(\int \frac{\mathrm{d} x}{\cos x(1+\cos x)}=\)
- A \(\log (\sec x+\tan x)+2 \tan \left(\frac{x}{2}\right)+c\), where \(c\) is the constant of integration
- B \(\log (\sec x+\tan x)-2 \tan \left(\frac{x}{2}\right)+c\), where \(c\) is the constant of integration
- C \(\log (\sec x+\tan x)+\tan \left(\frac{x}{2}\right)+c, \quad\) where \(c\) is the constant of integration
- D \(\log (\sec x+\tan x)-\tan \left(\frac{x}{2}\right)+c, \quad\) where \(c\) is the constant of integration
Answer & Solution
Correct Answer
(D) \(\log (\sec x+\tan x)-\tan \left(\frac{x}{2}\right)+c, \quad\) where \(c\) is the constant of integration
Step-by-step Solution
Detailed explanation
\(\int \frac{\mathrm{d} x}{\cos x(1+\cos x)} = \int \left(\frac{1}{\cos x} - \frac{1}{1+\cos x}\right) \mathrm{d}x\) \(= \int \sec x \, \mathrm{d}x - \int \frac{1}{2\cos^2(\frac{x}{2})} \, \mathrm{d}x\)
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