MHT CET · Maths · Indefinite Integration
\(\int \frac{\mathrm{d} x}{3 \cos 2 x+5}\) equals
- A \(\frac{1}{2} \tan ^{-1}(\tan x)+c \quad, \quad\) where \(c\) is the constant of integration.
- B \(\frac{1}{2} \tan ^{-1}\left(\frac{\tan x}{2}\right)+c, \quad\) where \(c\) is the constant of integration.
- C \(\frac{1}{4} \tan ^{-1}\left(\frac{1}{2} \tan x\right)+c\), where \(c\) is the constant of integration.
- D \(\frac{1}{4} \tan ^{-1}(\tan x)+\mathrm{c}, \quad\) where c is the constant of integration.
Answer & Solution
Correct Answer
(C) \(\frac{1}{4} \tan ^{-1}\left(\frac{1}{2} \tan x\right)+c\), where \(c\) is the constant of integration.
Step-by-step Solution
Detailed explanation
\( \int \frac{\mathrm{d} x}{3 \cos 2 x+5} = \int \frac{\mathrm{d} x}{3 \left(\frac{1-\tan^2 x}{1+\tan^2 x}\right)+5} \) \( = \int \frac{(1+\tan^2 x) \, \mathrm{d} x}{3(1-\tan^2 x)+5(1+\tan^2 x)} = \int \frac{(1+\tan^2 x) \, \mathrm{d} x}{8+2\tan^2 x} \)
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